x^2+15x+45x=0

Solution for x^2+15x+45x=0 equation:

x^2+15x+45x=0

We add all the numbers together, and all the variables

x^2+60x=0

a = 1; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·1·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*1}=\frac{-120}{2}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*1}=\frac{0}{2}
=0
$